Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

f1(0) -> s1(0)
f1(s1(0)) -> s1(0)
f1(s1(s1(x))) -> f1(f1(s1(x)))

Q is empty.


QTRS
  ↳ Non-Overlap Check

Q restricted rewrite system:
The TRS R consists of the following rules:

f1(0) -> s1(0)
f1(s1(0)) -> s1(0)
f1(s1(s1(x))) -> f1(f1(s1(x)))

Q is empty.

The TRS is non-overlapping. Hence, we can switch to innermost.

↳ QTRS
  ↳ Non-Overlap Check
QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

f1(0) -> s1(0)
f1(s1(0)) -> s1(0)
f1(s1(s1(x))) -> f1(f1(s1(x)))

The set Q consists of the following terms:

f1(0)
f1(s1(0))
f1(s1(s1(x0)))


Q DP problem:
The TRS P consists of the following rules:

F1(s1(s1(x))) -> F1(f1(s1(x)))
F1(s1(s1(x))) -> F1(s1(x))

The TRS R consists of the following rules:

f1(0) -> s1(0)
f1(s1(0)) -> s1(0)
f1(s1(s1(x))) -> f1(f1(s1(x)))

The set Q consists of the following terms:

f1(0)
f1(s1(0))
f1(s1(s1(x0)))

We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
QDP
          ↳ QDPAfsSolverProof

Q DP problem:
The TRS P consists of the following rules:

F1(s1(s1(x))) -> F1(f1(s1(x)))
F1(s1(s1(x))) -> F1(s1(x))

The TRS R consists of the following rules:

f1(0) -> s1(0)
f1(s1(0)) -> s1(0)
f1(s1(s1(x))) -> f1(f1(s1(x)))

The set Q consists of the following terms:

f1(0)
f1(s1(0))
f1(s1(s1(x0)))

We have to consider all minimal (P,Q,R)-chains.
By using an argument filtering and a montonic ordering, at least one Dependency Pair of this SCC can be strictly oriented.

F1(s1(s1(x))) -> F1(s1(x))
Used argument filtering: F1(x1)  =  x1
s1(x1)  =  s1(x1)
f1(x1)  =  f1(x1)
0  =  0
Used ordering: Quasi Precedence: [s_1, f_1]


↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ QDPAfsSolverProof
QDP

Q DP problem:
The TRS P consists of the following rules:

F1(s1(s1(x))) -> F1(f1(s1(x)))

The TRS R consists of the following rules:

f1(0) -> s1(0)
f1(s1(0)) -> s1(0)
f1(s1(s1(x))) -> f1(f1(s1(x)))

The set Q consists of the following terms:

f1(0)
f1(s1(0))
f1(s1(s1(x0)))

We have to consider all minimal (P,Q,R)-chains.